2y^2+8y=-16

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Solution for 2y^2+8y=-16 equation:



2y^2+8y=-16
We move all terms to the left:
2y^2+8y-(-16)=0
We add all the numbers together, and all the variables
2y^2+8y+16=0
a = 2; b = 8; c = +16;
Δ = b2-4ac
Δ = 82-4·2·16
Δ = -64
Delta is less than zero, so there is no solution for the equation

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